Question

4y^2/3y^2-6y+3 x 3y-3/2y solve.
i got as far as 12y^3-12y^2 / 6y^3-12y^2+6y and now am stuck

Answer 1

I have no idea what equation to work with.

Answer 2

factor the second numerator and the first denominator first\[=\frac{4y^2}{3(y-1)^2}*\frac{3(y-1)}{2y}\]the y-1 expression will cancel; the 3's will cancel; the 4 and the 2 will reduce; and the y^2 and the ywill reduce\[=\frac{2y}{y-1}\]

Answer 3

did i skip too many steps

Answer 4

nope :) thank you!

Answer 5

cool! :})