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subtract 8-v/v-6 - 4v-9/6-v
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get a common denominator of (v-6)
multiply the 2nd equation by (-1) to get denominator in form of (v-6) and then work on numerators
3v+17/v-6 ??
nope, how about -5v-1/v-6?
I am sorry, I mean multiply the 2nd fraction by (-1)/(-1)
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3v-1/v-6
(8-v)/(v-6)-(4v-9)/(6-v)= (8-v)/(v-6)-(4v-9)(-1)/(6-v)(-1)= (8-v)/(v-6)+(4v-9)/(v-6)=(8-v+4v-9)/(v-6)=(3v-1)/(v-6)
whew! finally got it lol
good for you. It's very often will be used in your class.
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