How many 4-digit positive integers can be made using the digits 0,1,2,3,4,5 and repetitions of digits are not allowed?
4096
6*6*6*6 = 6^4
oh wait
you might have to remove some trivial cases
the answer at the book is 300 but i don't know how to arrive at the answer
ok it is 5*6*6*6
oh repetition not allowed
so 5*5*4*3
so thats 300
why is the second number 5
ok let me explain the logic
the first number in the thousandth's place is to choose from { 1,2,3,4,5} , for the hundreth place you can choose 0 , so you again have 5 choices .
so for example , if you choose 1 for thousandth place, then you have { 0,2,3,4,5} numbers to choose for hundredth place.
ooohhh that make sense. I thought it was 5,6,4,3 thanks a lot
if you choose 3 for hundreth place, then you have { 0,2,4,5} for tens place
5643?
oh 5*6*4*3
you're right, it is 5,5,4,3
the trick is you have to add zero to the second choice, third, etc
yup
the zero does not apply to the first choice. so its tricky ;)
thanks again
also to be clear they should say that 0430 is not a 4 digit number for example
also interesting you have to do the choices in order, you cant skip around
this is called multiplication principle by the way
jm, any questions?
5*5*4*3 = 300 Cannot use 0 for the thousands digit, therefore, one of the 5 non-zero digits can be chosen. For the hundreds digit, 0 and 4 of the other numbers can be chosen. The tens digit 4 and the units digit 3.
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