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How do you find the lim x-> ∞ of tan(π/4cos(sin x^1/3))? Please be thorough thanks!
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The function is this? \[\tan\left( \pi/4 . \cos(\sin(x^{1/3})) \right)\]
yes
Then think about whether or not sin(x^{1/3}) has a limit as x --> infinity Remember that sin oscillates without end.
the limit does not exist as x-> infinity for sin (x^1/3)\[\sin x^{1/3}\]
Right. Hence does your function have a limit as x --> infinity ?
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I'm going to say no
And you'd be right.
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