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OpenStudy (anonymous):
factor by grouping 6x^3-6x^2-x-1
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jimthompson5910 (jim_thompson5910):
Are you sure it's not 6x^3-6x^2-x+1 ?
jimthompson5910 (jim_thompson5910):
or something similar
OpenStudy (anonymous):
sorry you are right it is
jimthompson5910 (jim_thompson5910):
6x^3-6x^2-x+1 (6x^3-6x^2)+(-x+1) 6x^2(x-1)-1(x-1) (6x^2-1)(x-1) So 6x^3-6x^2-x+1 factors to (6x^2-1)(x-1) In other words, 6x^3-6x^2-x+1=(6x^2-1)(x-1)
OpenStudy (anonymous):
could they make it where there was not so many numbers off that back huh? lol
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jimthompson5910 (jim_thompson5910):
lol that's why x was introduced, to reduce the amount of numbers on the page
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