Question

solve
49b^2-4=0

Answer 1

49b^2-4=0


(7b-2)(7b+2)=0


7b-2=0 or 7b+2=0


7b=2 or 7b=-2


b=2/7 or b=-2/7

Answer 2

\[b = \pm \sqrt{\frac{4}{49}}\rightarrow2/7\]

Answer 3

\[b = \pm \sqrt{\frac{4}{49}}\rightarrow \pm \frac{2}{7}\]

Answer 4

\[49b^2-4\]
\[a^2-b^2=(a+b)(a-b)\]
\[(7b)^2-(2)^2=(7b+2)(7b-2)\]
\[(7b+2)(7b-2)=0\]
either 7b+2=0 or 7b-2=0
\[7b+2=0\]
\[b=\frac{-2}{7}\]
\[7b-2=0\]
\[7b=2\]
\[b=\frac{2}7\]
\[b=\pm{\frac{2}7}\]