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can someone derive this for me? f(x)=sin (cos (5x))
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f(x)=sin (cos (5x)) f'(x)=cos (cos (5x))*d/dx[cos(5x)] f'(x)=cos (cos (5x))*(-sin(5x))*d/dx[5x] f'(x)=cos (cos (5x))*(-sin(5x))*5x f'(x)=-5x*cos (cos (5x)*sin(5x)
ok, got it! thanks!! I had something similar, but missed a step...
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