4a-2 ≤a+1 ≤3a+4 please show steps?
Huh? the question is \[4a -2\le a +1\le 3a +4\] and I'm supposed to get something like x such as x is less than or equal to BLANK less than or equal to BLANK
4a -3 < a < 3a + 3
subtract 1 through out the inequallity
yeah i did that but i keep getting stuck
jm has done this for u
With what o.o
thats complete?????
this is complete, but u can get x coz there is no x :P
in the back of the book they ended up with -3/2 < a <1 ( < is less than or equal to )
4a-3<a 3a<3 a<1 next a<3a+3 -2a<3 a>-3/2 or -3/2<a combine both
-3/2<a<1 :)
thanks, I just could not figure it out but i thought whatever you did to one side you did everywhere and what you did on the first one isnt the same on the second
oh, if u r confused, u can ask
actually u have to split up to sides
on the first you did -1 then - a and +3 then divide by three but the second you did -1 then -3a then divide by negative 2
4a-2 ≤a+1 ≤3a+4 4a-2 ≤a+1 and a+1 ≤3a+4
see i thought if you did for example minus three you did it to bothe the first and second part
now solve them seperatley
no yeah i got you... im just saying i was confused because i thought if i did minus a on the left one i had to do minus a on the right thank you both
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