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Mathematics 19 Online
OpenStudy (anonymous):

4a-2 ≤a+1 ≤3a+4 please show steps?

OpenStudy (anonymous):

Huh? the question is \[4a -2\le a +1\le 3a +4\] and I'm supposed to get something like x such as x is less than or equal to BLANK less than or equal to BLANK

OpenStudy (anonymous):

4a -3 < a < 3a + 3

OpenStudy (anonymous):

subtract 1 through out the inequallity

OpenStudy (anonymous):

yeah i did that but i keep getting stuck

OpenStudy (anonymous):

jm has done this for u

OpenStudy (anonymous):

With what o.o

OpenStudy (anonymous):

thats complete?????

OpenStudy (anonymous):

this is complete, but u can get x coz there is no x :P

OpenStudy (anonymous):

in the back of the book they ended up with -3/2 < a <1 ( < is less than or equal to )

OpenStudy (anonymous):

4a-3<a 3a<3 a<1 next a<3a+3 -2a<3 a>-3/2 or -3/2<a combine both

OpenStudy (anonymous):

-3/2<a<1 :)

OpenStudy (anonymous):

thanks, I just could not figure it out but i thought whatever you did to one side you did everywhere and what you did on the first one isnt the same on the second

OpenStudy (anonymous):

oh, if u r confused, u can ask

OpenStudy (anonymous):

actually u have to split up to sides

OpenStudy (anonymous):

on the first you did -1 then - a and +3 then divide by three but the second you did -1 then -3a then divide by negative 2

OpenStudy (anonymous):

4a-2 ≤a+1 ≤3a+4 4a-2 ≤a+1 and a+1 ≤3a+4

OpenStudy (anonymous):

see i thought if you did for example minus three you did it to bothe the first and second part

OpenStudy (anonymous):

now solve them seperatley

OpenStudy (anonymous):

no yeah i got you... im just saying i was confused because i thought if i did minus a on the left one i had to do minus a on the right thank you both

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