Question

Derive another quotient property expressing tanx in terms of secx and cscx.

Answer 1

\[tan(x) = {sin(x)\over cos(x)}\]
And \[sec(x) = {1\over cos(x)}, csc(x) = {1\over sin(x)}\]
Using these equations you can also express the tangent as
\[tan(x) = {sec(x) \over csc(x)}\]