I'm confused. Why is the answer to l9/10+5xl<11/10, -2/5
do you mean\[\left| (9/10)+5x \right|<11/10\] or is it\[\left| 9/(10+5x) \right|<11/10\]
The first one
Sorry I used capital i's for the absolute value
If you need more info, watch Khan's video, (and the following one) http://www.khanacademy.org/video/absolute-value-inequalities-example-1?playlist=Algebra+I+Worked+Examples
-11/10<9/10+5x<11/10 subtract 9/10: -20/10<5x<2/10 -2<5x<1/5 divide by 5: -2/5<x<1/25 Since we only divided by 5 the direction of the signs did not change. Had we had to take a reciprocal, they would have. Consider 1/x<1/3 take the reciprocal: x>3 and the signs change. We can see this by multiplying both sides of 1/x<1/3 by 3x WITHOUT changing the sign: 3<x
I'm soooo confused but thanks.
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