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OpenStudy (anonymous):
Intercepts of 2x^2+4x+4?
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OpenStudy (anonymous):
Do you mean x-intercepts?
OpenStudy (anonymous):
x and y-intercepts
OpenStudy (amistre64):
divide off the 2; and complete the square perhaps; or just plug it into the quadratic formula
OpenStudy (amistre64):
the yint is when x=0; which amounts to the constant on the end
OpenStudy (anonymous):
thank you
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OpenStudy (anonymous):
yint=4?
OpenStudy (amistre64):
yep; or if its an ordered pair: (0,4)
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