Question

Use elimination to solve the system.

3x-12=5y
51-5y=4x

Answer 1

Why not use substitution? it is easier with subs.

Answer 2

3x-12=y
3x=y+12
x=(y+12)/3

51-5y=4x
51-5y = 4(y+12)/3
3(51-5y)=4(y+12)
153-15y = 4y+48
-15y-4y = 48-153
-19y = -105
y = -105/-19 = 5

Answer 3

the first eq states what 5t equals, then the second one uses 5y

Answer 4

*y, not t

Answer 5

Kush, you said:
3x-12=y
3x=y+12
x=(y+12)/3
but it isn't 3x-12=y
it is 5y

Answer 6

3x-12=5y
51-5y=4x
51-(3x-12)=4x
51-3x+12=4x
63 = 7x
x = 9
y = 3

Answer 7

I like subs too but i have to show work using elimination, which i get stumped on a lot

Answer 8

\[3x-12=5y\]
\[3x=5y+12\]
\[x=\frac{5y+12}3\]

\[51-5y=4x\]
\[51-5y=\frac{4(5y+12)}3\]
\[3(51-5y)=4(5y+12)\]
\[153-15y=20y+48\]
\[-15y-20y=48-153\]
\[-35y = -105\]
\[y=\frac{-105}{-35}\]
\[y=3\]\[x=9\]

Answer 9

3x-12=5y
51-5y=4x

ok, first set them up so like terms are in line vertically:
3x - 5y = 12
4x +5y = 51

Answer 10

then, since there is a +5y and a -5y, add the equations' terms:

3x - 5y = 12
4x +5y = 51
7x + 0 = 63
You can take it from there

Answer 11

i think there should be so much explaination needed .....tonks
shannon where r u stuck ? tell us we would clear ur doubt !