Find 3 consecutive odd integers whose sum is 225, explain please
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OpenStudy (anonymous):
sorry i ment 255
OpenStudy (zarkon):
\[n+n+2+n+4=225\]
\[3n+6=225\]
\[3n=219\]
\[n=73\]
so 73,75,77
OpenStudy (karatechopper):
x=1st number
x+2=2nd number
x+4=3rd number
x+x+2+x+4=225
combine like terms
3x+6=225
3x-6+6=225-6
3x=219
3x/3=219/3
x=73:first number
x+2=75:2nd number
x+4:3rd number
OpenStudy (karatechopper):
now if tht is 255 then.....
OpenStudy (zarkon):
n+n+2+n+4=255
3n+6=255
3n=249
n=83
so 83,85,87
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well i used to wonder the same thing, but my teacher just said tht when u have to add something odd together count by twos and u will get the right answer..
OpenStudy (anonymous):
ohh i get it, so if it was 4 numbers the 4th one will be x+6 right?
OpenStudy (karatechopper):
yes sir!
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