Find 3 consecutive odd integers whose sum is 225, explain please
sorry i ment 255
\[n+n+2+n+4=225\] \[3n+6=225\] \[3n=219\] \[n=73\] so 73,75,77
x=1st number x+2=2nd number x+4=3rd number x+x+2+x+4=225 combine like terms 3x+6=225 3x-6+6=225-6 3x=219 3x/3=219/3 x=73:first number x+2=75:2nd number x+4:3rd number
now if tht is 255 then.....
n+n+2+n+4=255 3n+6=255 3n=249 n=83 so 83,85,87
x=1st x+2=2nd x+4=3rd x+x+2+x+4=255 combine like terms 3x+6=255 3x+6-6=255-6 3x=249 3x/3=249/3 x=83:1st x+2=85:2nd x+4=87:3rd
why did you put x+2 and x + 4?
well i used to wonder the same thing, but my teacher just said tht when u have to add something odd together count by twos and u will get the right answer..
ohh i get it, so if it was 4 numbers the 4th one will be x+6 right?
yes sir!
thanks! :)
Join our real-time social learning platform and learn together with your friends!