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Calculate the derivative of the following function. g(x)=sin(x^2)+(sinx)^2+sin(2x)+(sin2)x
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\[y=f(g(x)) =>y'=f'(g(x))g'(x)\] use chain rule
could you write the process?
you have to take the derivative of 4 terms. we already did the last one
derivative of \[\frac{d}{dx}\sin(x^2)=\cos(x^2)\times \frac{d}{dx}x^2=2x\cos(x^2)\] for the first term
g'(x)=2 cos(2 x)+2 x cos(x^2)+sin(2)+sin(2 x)
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