Question

How do you solve 3x^2=15?

Answer 1

divide both sides by 3
x^2 = 5
x = +sqrt 5 , - sqrt 5

Answer 2

x^2 = 5
x = sqrt 5

Answer 3

\[3x^2=15\]
You want to get divide 15 by 3 to get rid of the coefficient on the left side
So: \[x^2=5\]
Then you find the square root of that to get rid of the squared
Your answer should be: \[x= \pm \sqrt{5}\]

Answer 4

Okay, so then how would I solve 5x^2-3x=-8?

Answer 5

add 8 to both sides

Answer 6

then factor

Answer 7

you might have to apply the quadratic formula here

Answer 8

no, you don't.

5x^2 -5x + 8x + 8 = 0

i think you got the equation wrong, it should be

5x^2 - 3x = 8.

Answer 9

oh, wait, you need the quadratic eq if it's

5x^2 - 3x = -8.

Answer 10

oh really