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Solve 3x^2 + 4x = 2.
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3x^2+4x-2=0 quadratic formula from here. You know it, right?
Not quite.
apply quadratic formula first of all right it in standard form as 3x\[^{2}\]+4x-2=0 then write finally u get \[x=(-2\pm \sqrt{10})\div\]
where is my full answer:*(
It cut you off :(
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wait i will right again
is it divided my 3?
\[x=(-b \pm \sqrt{b^2-4ac})/2a\]
*by
yes diviided by 3
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where the quadratic is in the form ax^2+bx+c=0
3x^2+4x-2=0 \[x=(-b \pm \sqrt{b^2 -4ac})/2a\] \[x=(-4 \pm \sqrt{4^2 -4(3)(-2)})/2(3)\] \[x=(-4 \pm 2\sqrt{10})/6\]\[x=(-4+2\sqrt{10})/6\]or\[x=(-4-2\sqrt{10})/6\]
Oh okay well thank you :D
:)
simplify it by calculator
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