Question

(5x^2/3x^-4)^-1

Answer 1

the answer is 1/15x^6

Answer 2

or 15x^-6

Answer 3

\[3/x ^{4}/5x ^{2}=15x ^{2}/x ^{4}\]

Answer 4

\[15/x ^{2}\]

Answer 5

no that's not 15/x^2 look i'll do the steps

Answer 6

(5x^2/3x^-4)^-1=(5x^2/1/3x^4)^-1

Answer 7

(5x^2/1/3x^4)^-1=(5x^2*3x^4)^-1

Answer 8

(5x^2*3x^4)^-1=(15x^6)^-1

Answer 9

looke it newly there just x on exponent -4 -so 3 not is

Answer 10

ok ?

Answer 11

so check it newly

Answer 12

right ???

Answer 13

what are you talking about

Answer 14

check it there is just x on exponent minus 4

Answer 15

3 not is

Answer 16

ok, i'll do it again, thanks

Answer 17

well

Answer 18

but it's still not 15/x^2

Answer 19

why ?

Answer 20

(5x^2/3x^-4)^-1=(5x^2/3/x^4)^-1

(5x^2/3/x^4)^-1=(5x^2*x^4/3)^-1

Answer 21

(5x^2*x^4/3)^-1=(5x^6/3)^-1=3/5x^6

Answer 22

ok it's 3x^6/5

Answer 23

(5x^2/3x^-4)^-1=

(5x^2/3/x^4)^-1=

(5x^2*x^4/3)^-1=

(5x^6/3)^-1= 3/5x^6

Answer 24

that's my final answer :P