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x^3-18x+27
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(x-3)(x^2+3x-9)
what is the divisor
1
can you show me how you worked it out
the divisor of the coefficients (1,-18,27) is 1
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what r u dividing it by and will it come out to no remainder
o so you do want to factor
then it is x-3/the original equation
then do long division
you r dividing it by 1 but there will be a remainder
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no sry forget the 1 part: at first i thot u wanted me to factor but then when u said divisor i just thot u meant something else
soo what r we dividing by then if not 1
\[(x^{3}-18x+27) \div x-3\]
but it will not divide evenly
to figure out the x-3 part u sub in all factors of 27 til u can make the expression =0
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do long division
how do u do it with synthetic division
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