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Mathematics 16 Online
OpenStudy (anonymous):

x^3-18x+27

OpenStudy (anonymous):

(x-3)(x^2+3x-9)

OpenStudy (anonymous):

what is the divisor

OpenStudy (anonymous):

1

OpenStudy (anonymous):

can you show me how you worked it out

OpenStudy (anonymous):

the divisor of the coefficients (1,-18,27) is 1

OpenStudy (anonymous):

what r u dividing it by and will it come out to no remainder

OpenStudy (anonymous):

o so you do want to factor

OpenStudy (anonymous):

then it is x-3/the original equation

OpenStudy (anonymous):

then do long division

OpenStudy (anonymous):

you r dividing it by 1 but there will be a remainder

OpenStudy (anonymous):

no sry forget the 1 part: at first i thot u wanted me to factor but then when u said divisor i just thot u meant something else

OpenStudy (anonymous):

soo what r we dividing by then if not 1

OpenStudy (anonymous):

\[(x^{3}-18x+27) \div x-3\]

OpenStudy (anonymous):

but it will not divide evenly

OpenStudy (anonymous):

to figure out the x-3 part u sub in all factors of 27 til u can make the expression =0

OpenStudy (anonymous):

do long division

OpenStudy (anonymous):

how do u do it with synthetic division

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