Question

What are the x– and y–intercepts of the quadratic equation y = (x – 1)^2 – 16? Identify the x–intercepts by graphing the quadratic equation.

a) x–intercepts: (3, 0) and (–5, 0)
y–intercept: (0, –16)
b) x–intercepts: (–3, 0) and (5, 0)
y–intercept: (0, -15)
c) x–intercepts: (–3, 0) and (5, 0)
y–intercept: (0, –16)
d) x–intercepts: (3, 0) and (–5, 0)
y–intercept: (0, –15)

Answer 1

y intercept is what you get when your replace x by 0
it would be
\[y=(0-1)^2-16=1-16=-15

Answer 2

x intercept is what you get when you set y = 0
it would be
\[0=(x-1)^2-16\]
\[(x-1)^2=16\]
\[x-1=4\] or
\[x-1=-4\]
\[x=5\] or
\[x=-3\]

Answer 3

so y intercept is (0-15)
x intercepts are (-3,0) and (5,0)