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simplify (x^(-3)y^(-1))^-1
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Multiply the outer exponent by all the inner exponents to get x^((-3)*(-1))y^((-1)*(-1)) = x^3y^1 = x^3y So the answer is x^3y
no nut thnx anyway
but*
what's wrong?
x isnt bein set to one whole exponent its two expressions each with their own radical multiplied by each other and the entire expression is being put to the -1 power
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can you draw it out
|dw:1319079890625:dw|
yeah that's what I thought it was originally \[\Large (x^{-3}y^{-1})^{-1}=x^3y\]
ok thnx thought u meant x^(3y)
oh, no sry
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lol k thnx
probably should have just drawn it out lol
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