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set up a triple integral that gives the volume of the solid bounded by the coordinate planes and the plane 3x + 2y -z = 6
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x =0 , y = 0, z = -6 y = 0, z = 0, x = 2 x = 0, z= 0, y =3 \[\int\limits_{-6}^{0}\int\limits_{0}^{3}\int\limits_{0}^{2} 1 dx dy dz\]
done
No. That integral is the volume of a box. But the volume you want is some kind of triangular pyramid. So you need to be much more subtle with the limits of integration.
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