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f(x)=(x√+9)−x−6 f(√2+6) Solve the function.
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you need to rewrite the first part.... plug it in and work it.
i know but the radicals are messing me up
can u help or no?
i can if you clarify. is it sqrt(x)+9 or x+sqrt(9) or sqrt(x+9)?
and the second part. is it sqrt(2)+6 or sqrt(2+6)?
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f(x)=(√x+9)−x−6 BOTH X & 9 ARE UNDER RADICAL f(√2+6) ONLY 2 IS UNDER RADICAL
clear?
no need for caps, just needed clarification. f(x)=sqrt(x+9)-x-6 f(sqrt(2)+6)=sqrt(sqrt(2)+15)-sqrt(2) 2^(1/4)+15^(1/2)-2^(1/2)
didnt put it in CAPS to make it seem like an ahole or anything
*like im being an ahole
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thats not the answer btw :(
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