Question

help!

Answer 1

i still need some help lol

Answer 2

you do haha

Answer 3

911 man!

Answer 4

now wat?

Answer 5

great theres my man... ok check it out.. im gonna type.

Answer 6

:D

Answer 7

An object is thrown upward from the top of a 160 ft building with an initial velocity of 144 ft per second. The height h of the object after t seconds is given by the quadratic equation h=-16t^2+144t+160

Answer 8

when will the object hit the ground... in how many seconds.

Answer 9

you all can help as well

Answer 10

9.1

Answer 11

in what format does it need the answer?

Answer 12

... great... but how lol

Answer 13

just the time

Answer 14

we have to solve it by quadratic formula.

Answer 15

ok...

Answer 16

like the +-b square root of blah blah blah

Answer 17

lol, yea!

Answer 18

dont i just put the height it took for the ball to reach 144 ft which is in one second...

144=-16t^2+144t+160

Answer 19

no right... how stupid

Answer 20

LOL, you are right, that's the first step.

Answer 21

oh ok

Answer 22

More help/

Answer 23

yes im stuck on the factoring of -16t^2+144t+16

Answer 24

which was only one step after...

Answer 25

this can't be factored..

Answer 26

LOL.

Answer 27

what?

Answer 28

cuz of the negative?

Answer 29

Nope, because it dont have such values which can be factored. LOL.

Answer 30

really? so how can i do it?

Answer 31

quadratic formula.

Answer 32

you mean pythagorean theorum right?

Answer 33

NOO!!
that +- b thing.

Answer 34

right ok i confused them sorry

Answer 35

\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 36

u said you got 9.1 right?

Answer 37

im stuck

Answer 38

i got 2 values, 9.1 is the positive one.

Answer 39

i got -144+- 21760/-32

Answer 40

im lost

Answer 41

Same here. LOL.