A passenger is pulling on the strap of a 14.0-kg suitcase with a force of 75.5 N. The strap makes an angle of 34.5° above the horizontal. A 37.8-N friction force opposes the motion (horizontal) of the suitcase. Determine the acceleration of the suitcase.

Question

anonymous · Answer

Draw free body diagram and notice that the friction force is pointing in the opposite direction that the passenger is pulling the suitcase. This means the net force of acting on the object will be equal to the pull force minus the frictional force (F= (force by person)-(frictional force)). Newton's second law state F=mass(acceleration). Plug in F and solve for a.

anonymous · Answer

frictional force along the horizontal axis is just 37.8. The force by the person along the horizontal axis is 75.5(Cos[34.5])

anonymous · Answer

This could be wrong but that's the best I got. Hope this helps.