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Find y '' by implicit differentiation 9x^2 + y^2 = 9....i got y '...idk how to find y''
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I got that y ' = -9x /y but how do u find y''?
differentiate again, using quotient rule
u=-9x du/dx= -9 v= y dv/dx = dy/dx = y'
Please check my working before use
im confused what u are doing to get y '' thou
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liek what rule or formula are u using
so \[y'' = \frac{-9y - ( -9x)(y') }{y^2}\]
then sub in y' = -9x/y
wait how did u get what y '' is ....like how is it -9y - (-9x) etc....
quotient rule.
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so what shud the final answer be
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