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8-4(2-x)=<-2x use interval notation
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8 - 8 + 4x ≤ -2x 6x ≤ 0 x ≤ 0 Range of x: [-∞ , 0]
(-∞ , 0] this is z answer
Well, Kira Yamato's answer could only imply (-∞ , 0], when dealing with infinity we can't use Closed interval in the unbound side.
But we can't rule out that possibility since < is part of ≤
≤ would only impose the closed interval on the '0' side,however the infinity side is free from any change.
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infinity can never be closed!!!
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