Question

identify the vertex, axis of symmetry and x-intercepts then check your results algebraically for g(x)=x^2+8x+11 (Show work please)

Answer 1

anyone? Medal for a good answer:)

Answer 2

Calculate the x intercepts using the quadratic formula which results in \[-4\pm \sqrt{5}\] That is a start.

Answer 3

The function is already in standard form with a=1, and b=8
h=-b/2a
h=-8/2=-4 substitute -4 for x in the function to obtain y
(-4)^2 +8(-4)+11=16-32+11=-5 y=-5 vertex is at (-4,-5)
Since the coefficient of x^2 is positive the parabola opens upward.

Answer 4

I would assume the axis of symmetry would be the vertical line x=-4