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OpenStudy (anonymous):
A bag contains a total of 20 batteries, of which six are defective. Selecting two at random, without replacement, determine the probability that ONE of the batteries you select are good.
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OpenStudy (anonymous):
I know that for two good batteries, it's 16C2/20C2
OpenStudy (anonymous):
(For 4 batteries that is)
OpenStudy (a_clan):
(14C1 * 6C1) /20C2 + (6C1 * 14C1)/20C2
OpenStudy (anonymous):
Can you just multiply 14C1 * 6C1 / 20C2 by two then?
OpenStudy (a_clan):
yes. It was for explanation.
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OpenStudy (anonymous):
Thank you
OpenStudy (anonymous):
By the way, your answer was not correct. It's simply the first part, and not x2
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