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absvl x+2>5 solve algebraically
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http://www.sosmath.com/algebra/inequalities/ineq01/ineq01.html x + 2 > 5 x > 5 - 2 x > 3
solution -> (inf, 3)
thank you
do you need an explanation of the answer ?
The question uses absolute value, but is unclear about what it applies to. I'll assume the problem is really |x+2| > 5 That's really two inequalities, and you have to figure out if they're related with "and" or "or". (x+2) > 5 (x+2)<-5 Well, something can't be greater than 5 AND less than -5, so it must be OR. (x+2)>5 x>3 x+2<-5 x<-7 So the solution is the union of the two regions x>3 and x<-7. Notice it excludes the points 3 and -7.
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