Question

how do you find the zeros of a polynomial in y = ax^2 + bx + c ?

Answer 1

x_1,_2=(-b+/- sqrt(b2-4ac))/2a

Answer 2

quadratic formula

Answer 3

factor things out so that youe left with something like (hx + d)(gx + e). set each thing in the ( ) = to 0, like (hx + d) = 0, then solve for x.
x^2 + 3x + 2 = 0
(x + 1)(x + 2) = 0
(x + 1) = 0, (x + 2) = 0
x = -1, and -2