Question

Find the real number solutions of the equation:
g^3+3g^2-g-3=0
I don't get how to do this. =/ Help!

Answer 1

factor

Answer 2

g=1

Answer 3

preferably by grouping

Answer 4

one answer is g=1 to c if there is more devide function by (g-1)

Answer 5

(g-1) is a factor so you could divide synthetically, giving you a quadratic which is solvable.

Answer 6

answers are -3,1,-1

Answer 7

great, just give out the answer

Answer 8

(g-1)(g^2+4g+3)
is what you get after division, which factors into
(g-1)(g+1)(g+3)

Answer 9

g2(g+3)-(g+3)=(g2-1)(g+3)

Answer 10

Thanks everyone, that really helped. :)