Four times the lesser of two consecutive integers is 12 less than twice the greater number. Find the integer. Does anyone know how to solve that???
myininaya does
I don't see it that way
oops
wait now i'm confused :(
you must be getting tired. i know i am doesn't anyone go out on a saturday night? no wonder the economy is bad
satellite don't be mad i accidently deleted yours i meant to delete mine
lol
power corrupts!
lol
write how you read it
that is one way to win a math war
first number \[n\] second number \[n+1\] four times the first number \[4n\] two times the second \[2(n+1)\] and it is 12 less so you get \[4n=2(n+1)-12\]
oh i'm idiot
i am going to be a moderator and delete all answers above the level of neophyte
lesser of the two integers lol
except zarkon's of course
ty
yw
i thought i was looking at my name when i was deleting my eyes played tricks on me
thank you all for helping me. I really needed to get this done so I will probably be online with more questions :D
post away. as you can see they provide hours of amusement.
lol wow now i feel really stupid because i have another question
that was really fast
my question is...
two times the least of three consecutive odd integers exceeds three times the greatest by 15 what are the integers???
your on. i going to bed
two times the least of three consecutive odd integers exceeds three times the greatest by 15 what are the integers???
kk bye bye
suppose n is odd the next odd integer is n+2 the next next odd integer of n is n+4 n<n+2<n+4 so n is the smaller or the least of these 3 integers so we have 2 times the least of three consecutives has the following representation: 2n
and then we have exceeds three times the greatest by 15
what is the greatest number here?
n n+2 or n+4 ?
thank you for helping
so you answered n+4 right?
because that is correct
we have 3 times that
2n-15=3(n+4) ^ | don't forget about the exceeds by 15 part
thanks so much!!!!!!!
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