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3x-1 + 4-5x 5 6
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Use the equation tab to put in your question in the correct form so I can help you please!
i don't know how to do this... uhmm.. it's like: 3x - 1, all over 5 plus 4-5x, allover 6
For division, use the / sign.
\[[(3x-1)/5] + [(4-5x)/6]\] is this correct?
Is the question asking you to solve for x?
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yes. i'm thinking maybe you'll think it's 3x-1/5 instead of 3x-1 allover 5
no not to look for x just to perform the operation
First, find your common denominator. Post that when you have it.
i'm really bad at math
30 is the lcd
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i'm worse at fractions
Right! So your next step would look like: \[{[6(3x - 1)]/30} + {[5(4-5x)/30]}\]
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