Question

whats the vertex of q (x)=x^2+6x+5

Answer 1

(x+1)(x+5)

Answer 2

to find the vertex use
\[x=-\frac{b}{2a}\] for the first coordinate

Answer 3

in this case you have
\[q(x)=x^2+6x+5\] so
\[-\frac{b}{2a}=-\frac{6}{2}=-3\] for the first coordinate of the vertex. replace x by -3 to find the second coordinate

Answer 4

q (x)=x^2+6x+5
=x^2+2*x*3 + 9 -4
=(x-3)^2-4
=a(x-h)^2-k
vertex(h,k)=(-3,4)