Determine the nature of the solutions of the equation x^2-12x+36=0
Well, what is the value of b^2 - 4ac for this equation and what does that value imply?
Cali, you don't need to delete your questions anymore.
my questions are filling up the board and making it go slower right?
i think you are supposed to recognize this as a "perfect square" i.e. \[(x-b)^2=x^2-12x+36=0\] see if you recognize b.
I recognize b
we know you do hero, your good at this crap. i am dumb as hell at math
Well, you could figure it out by factoring
and everyone who has been so kind in the past to me are now making fun of me for not understanding
I hope I wasn't one of them. Why do you always think people are making fun of you. You shouldn't think like that. There are many people who don't understand this stuff.
This equation either has one real, two real, or two non real solutions
x=6
Yes, it only has one solution. That is correct. Looks like James J had the right approach all along
thanks, it took some time, but figured it out
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