Question

5x^3-6y^3+6x^2y-5xy^2

Answer 1

Tricky, tricky... must be close to Halloween!

Given expression\[5x^3-6y^3+6x^2y-5xy^2\]Move the third term to be the first, and the first to be the third\[=6x^2y-6y^3+5x^3-5xy^2\]Now factor by grouping: factor the GCF from the first two and second two terms\[=6y(x^2-y^2)+5x(x^2-y^2)\]Factor out the binomial as a GCF\[=(x^2-y^2)(6y+5x)\]Now factor the difference of squares, and (I will) commute the terms in the second binomial (since I'm a little neurotic)\[=(x-y)(x+y)(5x+6y)\]this is the factored form.