e^x = 5 - 2x
Does anyone know how to go about solving this?

Question

anonymous · Answer

use ln base that way u cancel e

agentnao · Answer

I know, we did that. But then what?

anonymous · Answer

ln^(5-2x)

hero · Answer

I've seen something like this before. It's like you liberate x on one side and then trap it on the other side

anonymous · Answer

$$\ln5/ \ln(2x)$$

hero · Answer

Yes, but you're supposed to solve for x

agentnao · Answer

We've tried everything. Tell me when you get a numerical value and how you got it.

anonymous · Answer

LOL HERO

hero · Answer

Numerical solution is 1.0587. There's no known way to solve this algebraically.

agentnao · Answer

What! Really? So then how did you get it?

anonymous · Answer

graph the line, graph e^x and see where they intersect using a calculator or perhaps here http://www.wolframalpha.com/input/?i=e%5Ex+%3D+5+-+2x

anonymous · Answer

I shall find a way >=D

agentnao · Answer

Oh! Wow, thank you satellite! And Hero!

hero · Answer

Outkast, I think I know why you were laughing at me. But I think you might want to laugh at yourself.

anonymous · Answer

I really don't see an algebraic way

anonymous · Answer

I'm not going to say anything as there is nothing I can say that should be up on OpenStudy. I guess trying to put things behind absolutely is absurd for this situation

hero · Answer

I normally wouldn't have anything to say to you outkast, but the situation called for it.