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Calculus question: Find the intervals on which f is increasing and decreasing. f(x) = cos^2(x) on (-π,π)
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i took the derivative and i got f'(x) = -2sinxcosx. then i set it equal to zero and i solved and got x=(6nπ)/2. I'm not sure what I'm suppose to do next... Also I don't know if i solved right...
do you have geogebra? its a program you can download that you can enter the equation in and it will show you the graph.
my professor uses it all the time so we can see where the concaves and the increases and decreases are
i took the derivative and i got f'(x) = -2sinxcosx. then i set it equal to zero and i solved and got x=(6nπ)/2. I'm not sure what I'm suppose to do next... Also I don't know if i solved right...
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