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Mathematics 21 Online
OpenStudy (technodynamic):

I already solved Part A: h(x)= 3, -2, -5, -6, -5, -2 Help me for Parts (B-D) and show step-by-step.

OpenStudy (technodynamic):

hero (hero):

Composition of functions is really easy. Don't give up just yet!

OpenStudy (technodynamic):

the first part was easy

hero (hero):

Okay, then, whatever f(x) is you multiply it by 4. That's what j(x) = 4f(x) means. Don't let the notation scare you.

hero (hero):

I think you can figure it out. The values for f(x) are given. So take each value and multiply it by 4 and put it in the appropriate box

hero (hero):

Are you doing these currently or no?

OpenStudy (technodynamic):

Yeah. I came up w/

hero (hero):

With what?

OpenStudy (technodynamic):

-4, -12, -20, -28, -36, -44

hero (hero):

So you multiplied each number by 4, good. Wasn't so bad, huh?

OpenStudy (technodynamic):

lol true

OpenStudy (technodynamic):

For part C, there's a (g(x))^2? I don't understand what that represents?

hero (hero):

now for the next one, you simply take the given values of g(x) and square them. Then place them in the appropriate box

hero (hero):

Whatever the values for g(x) in the boxes above, take each value and square it. And then put those values where it says k(x)

OpenStudy (technodynamic):

16, 1, 0, 1, 16, 81

hero (hero):

Good

hero (hero):

Once again, easy

OpenStudy (technodynamic):

what about for part d?

hero (hero):

just division. Take the values for g(x) and then divide them by the values for f(x). In some cases, you will get fractions, but that's okay. Leave them as fractions.

hero (hero):

They could have made this much harder, but this is very easy.

OpenStudy (technodynamic):

haha alright. i came up w/ -4, -1/3, -0/5, -1/7, -4/9, and -9/11

hero (hero):

Yep. So much for withdrawing from the course. You've got this all figured out.

hero (hero):

Remember, nothing is ever as hard as it seems.

OpenStudy (technodynamic):

Thanks man, i appreciate it

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