Question

x^(2/3) + y^ (2/3) = 4
how would you find an equation for the tangent line at the point (-3sqrt3, 1) using implicit differentiation?

Answer 1

start with
\[\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}y'=0\] then replace x and y by the numbers you are given and solve for
\[y'\]

Answer 2

you get a decimal for the slope if you do that though :/

Answer 3

i agree, you can find a decimal approximation. that is not surprising is it?

Answer 4

the answer isn't suppose to contain a decimal according to our assignment