Question

rewrite the function in intercept form y=x^2+8x+15

Answer 1

Intercept form is for lines, and that is the equation for a parabola.

Do you need help finding the points where this parabola intercepts the x-axis?

Answer 2

yes

Answer 3

To do that, you need to set it all to zero and factor:

x^2+8x+15 = 0
(x+5)(x+3) = 0

then put both those in parentheses chunks in their own equations

x + 5 = 0
x + 3 = 0

and then simplify

x = -5
x = -3

So the two points where the parabola crosses the x-axis are -5 and -3.

Answer 4

Or, since we set y equal to zero in the beginning, in coordinate form it would be (-5,0) and (-3, 0)