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2x√4x^3-2x^2+12x
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2x/(4x^3 - 2x^2 + 12x) = 2/(4x^2 - 2x + 12) = 1/(2x^2 - x + 6)
ummm i don't think that's it :/ i'll give an example of a different problem i had hold on
x-3 / x^4-2 so i have to fill in the other ^ powers so it turns into x-3 / x^4 +0^3 + 0^2 -2 and the answer was x^3+3x^2+9x+25
are those 0^3 and 0^2 supposed to be x^3 and x^2 ?
sorta, but when it doesn't give any x values, you will them in as zero's. that's just how i was taught anyways
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Ok. So its (x^4 - 2) / (x-3) But this equals x^3+3x^2+9x+79/(x-3)+27, which is not exactly what you got. Let me start with (4x^3-2x^2+12x)/(2x) Answer: 2 x^2-x+6
You simply divide each term in the numerator by 2x
awww perfect!! thank you :)
np - btw is ftw a car? :)
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