three time a number s plus 4 times a number y is 1 more than 6 times the number s . solve for s
3s + 4y - 1 = 6s 4y - 1 = 6s - 3s 4y - 1 = 3s 4y -1 ----- = s 3
thanks
I have one more question
go ahead
five times a number k minus 9 is two-third of a number j. solve for j
what did you substract -1 instead of adding 1 on problem 1
help me please
you there, harkirat?
help
help me please
first I will attend to the previous question three time a number s = 3s 4 times a number y = 4y so three time a number s plus 4 times a number y = 3s + 4y then 6 times the number s = 6s Your problem states "three time a number s plus 4 times a number y is 1 more than 6 times the number s" this means that 3s + 4y is one more than 6s this means that 6s is 1 less than 3s + 4y so if we subtract 1 from 3s + 4y then it becomes equal to 6s that is why 3s + 4y - 1 = 6s Understood ????
Have patience, I am working on yr question only.....
thanks
Now coming to the second question five times a number k minus 9 is two-third of a number j. solve for j five times a number k minus 9 = 5k - 9 2 two-third of a number j = --- j 3 2 5k - 9 = = --- j 3 Multiplying both sides by 3 3(5k - 9) = 2j 15k - 27 = 2j 15k - 27 -------- = j 2
Got a medal for me ................☺
why muliplty by 3?
2/3m+a=a+c solve for m
2/3m+a=a+c solve for m
2/3m+a=a+c solve for m
I'll get you a medal
to get rid of the 3 in the denominator on right hand side .....
2/3m+a=a+c solve for m
oh ok
why don't u give it a try.......... u will not learn unless u try to do them yrself....
m=5/3c
I did them, now I am checking them
is m=5/3c correct?
no...
why not?
use the draw box to show me what u did...
2/3m+a=a+c solve for m
substract a then a will cancel out. mulipty by 3/2 to cancel out
m=5/3c
can you show me the answer?
whats the answer
see my draw box coming up....
|dw:1318962742144:dw|
Join our real-time social learning platform and learn together with your friends!