Question

i really don't get it i actually tried

4x - 32y / 4

http://tinypic.com/view.php?pic=s4qp3s&s=7

Answer 1

\[\frac{4(x-8y)}{4}\]
\[\frac{\cancel 4(x-8y)}{\cancel 4}\]
\[x-8y\]

Answer 2

4x-32y, find something in common. 1, 2, and 4. Let's take the largest factor out, 4. 4(x-8y)/4. Now, since there is 2 4's, you can cancel them out. You are left with, as stated above in saifoo's answer, x-8y