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lim as x approaches 0 from the right of x^(1/2)ln(7x). how do you know to change it to ln(7x)/x^(-1/2)?
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because just by making it negative is the same as putting it on the denominator of the fraction. X^1/2 = sqrt(x) and x^-1/2= 1/sqrt(x)... but in order to solve that problem, you need to graph it, look at the x=0 value from the right.
ok well we were told to use lahopital rule and i cant understand which to put on top or bottom
ah la hôpital, unfotunaly our AP calc class has not gotten that far, otherwise id love to help, sorry :(
haha np lol ty though
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