write the equation of a line that is parallel to 4x=3y=7 and also passes through the point (-5,2)
4x+3y=7?
yes
you need to find the slope of that line 3y=-4x+7 y=-(4/3)x+7/3 then you have a point and the slope of the new line, so using point slope form, y-2=-(4/3)(x+5)
im very lost after u find the slope
you dont know the slope when the equation of the line is in standard form, so you have to change it to a different form, the easiest form being slope intercept. so to find slope intercept form you solve for y, which is what i did. slope intercept form is y=mx+b where m is the slope. so -(4/3) is the slope. the using the point given, you can find the equation of the parallel line because it will have the same slope.
then i just took the slope and point and used them to figure out the new equation. point slope form is \[y-y_{1}^{}=m(x-x _{1}^{})\]so y1=2 and x1=-5
and m = -(4/3)
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