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If line 'q' bisects line EG at point T, and if ET = 1/3x and TG = x-2, then find EG.
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do you have a picture?
Let me try to draw one.
Are EG and ET equidistant?
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Alright, this is what I would do. Since ET is much longer than EG, I would set an equation as 1/3x - (x-2). That that sound okay?
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Directions: USe the definition of a segment of angle bisector to answer the question below. So I guess so, yes.
But that does not mean the angles are equal. It just means there is an equal distance from ET to TG
Okay let me try that.
Okay then. You need to set it up as : ET=TG. The equation will then be 1/3x =(x-2)
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