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Digital logic : Proving that A△B= ~A△~B?
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I don't see how you can show this I know that A△B = (A ∩ ~B) ∪ (~A ∩ B).
is that and?
sorry?
sorry i don't know what operator that is
can't help if you don't know either
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the delta?
it's symmetric difference of sets A and B
symmetric difference?
yeah like the set that contains those elements that are either in A or in B but not both
ok so that is the definition that you gave me above right i those what union means lol did you try constructing a truth table
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i mean i know what union means*
I don't see how? Like I'm kind of new with the union notation
|dw:1319346076348:dw|
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