2x^4-4x^2-48.
(a) Find all the real zeros of the polynomial function.
b) Determine the multiplicity of each zero and the number of turning points of the graph of the function.
(c) The number of turning points.

Question

2x^4-4x^2-48. 
(a) Find all the real zeros of the polynomial function. 
b) Determine the multiplicity of each zero and the number of turning points of the graph of the function. 
(c) The number of turning points.

amistre64 · Answer

step one is to factor out the commons

amistre64 · Answer

its also best to see this as a quadratic in disguise; say u=x^2 and rewrite

amistre64 · Answer

2u^2-4u -48

2 (u^2-2u -12)

amistre64 · Answer

now its pretty much a normal factoring or the quad formula

amistre64 · Answer

1/2 * 2 +- sqrt(100)

so its u = 6 or u = 4 i think

amistre64 · Answer

-12 up there should be -24

amistre64 · Answer

u = x^2 ; and u = 6 or 4

6 = x^2  x = +- sqrt(6)

4 = x^2; x = +- 2

amistre64 · Answer

tag and test

anonymous · Answer

So do I plug in -/+ 2 and -/+ sqrt(6) into the equation?

amistre64 · Answer

to test?  yes.  since that is what we found it would be good to test them to see if they actually work