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can you please show me how to solve for v? 8=1/2at^2+vt
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This is a quadratic equation where t is the variable. Move everything to one side of the equal sign and use the quadratic equation. \(\frac{1}{2}at^2 + vt - 8 =0 \)
subtract off the 1/2at^2 from each side then divide off the t to get v all by its little lonesome
later on in physics you might come across this equation, but for now ...
\[½at ^{2}+vt−8=0\] \[vt−8=-½at ^{2}\] \[vt=-½at ^{2} +8\] \[v=[-½at ^{2} +8]/t\]
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